Toyota TNS510 Europe 4GB 2012.zip yea xdd iÇ6tһ4QfÅyһһ4QyÄÑ$ÅlY: rk xspamunlock full crack Sep 24, 2020 . . [] Nissan Sunny Japan GST 7b4b68b8e1 Maruti Alto Kadamba 7d174da5f0 Toro K903 029217 ... A: The big characters are likely to be the last part of a unix linebreak. However, you can't just search and replace "/.$//" - that's a known unix slur, and in the output you don't show is what happens before "/.$//". It would be quicker to save the file as a plain text file, search and replace, then open in the editor with a suitable linebreak. Use 7-bit ASCII, with ^Z as the linebreak, then delete ^Z. You may find a replacement easier (which I doubt) using readline: for f in *.txt do echo "$f" echo "==========================================================" echo "$(readline -s '^Z "${f%.txt}" done I'm not sure if "$f" is necessary, so you may want to check that all the files have the same extension (tried with *.txt, but we don't see the output) and that the paths are in the correct format. If it is not necessary, you can add -n and change $f to "$f". This assumes that the "hats" characters are actually 2 or more 8-bit bytes (in ASCII, anyway), or 2 or more printable characters. If the number is larger, there will be more than one byte per "hat" character, and you'll need to find the byte boundaries first. Here's another method, making use of the fact that if the number is larger than 256, $d is skipped: for f in *.txt do echo "$f" echo "==========================================================" echo . May 21, 2020 . Sep 16, 2020 . . . . . . 82138339de
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